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How to copy a list in Python

May 30, 2025
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Claude and the Anthropic Team
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Copying lists in Python requires careful consideration of reference behavior and memory management. Python offers multiple built-in methods to duplicate lists, each with distinct implications for how the copied data behaves in memory.

This guide covers essential list copying techniques, practical tips, and real-world applications, with code examples created using Claude, an AI assistant built by Anthropic. You'll learn to handle both shallow and deep copies effectively.

Using the slice operator [:]

original_list = [1, 2, 3, 4, 5]
copied_list = original_list[:]
print(f"Original: {original_list}")
print(f"Copy: {copied_list}")
Original: [1, 2, 3, 4, 5]
Copy: [1, 2, 3, 4, 5]

The slice operator [:] creates a new list by copying all elements from the original list. This method performs a shallow copy, meaning it creates new references to the top-level elements while maintaining the same references for nested objects.

When you use original_list[:], Python allocates new memory for the copied list structure but doesn't duplicate the actual objects inside. This approach offers two key benefits:

  • Memory efficiency for simple lists containing immutable types like numbers or strings
  • Faster execution compared to deep copy methods since it only copies the outer container

Basic copying methods

Beyond the slice operator, Python provides several built-in methods to copy lists, including list(), .copy(), and list comprehension—each offering unique advantages for different scenarios.

Using the list() constructor

original_list = [1, 2, 3, 4, 5]
copied_list = list(original_list)
print(copied_list)
print(f"Same object? {copied_list is original_list}")
[1, 2, 3, 4, 5]
Same object? False

The list() constructor creates a new list object by iterating through the elements of the original list. This method performs a shallow copy, similar to the slice operator we discussed earlier.

  • The list(original_list) syntax creates a distinct list object in memory, as shown by the is operator returning False
  • Python allocates new memory for the copied list structure while maintaining references to the original nested objects
  • This approach works efficiently with both iterables and list-like objects, making it more versatile than slice notation

The constructor method particularly shines when working with other sequence types. It seamlessly converts tuples, sets, or any iterable into a new list while maintaining clean, readable code.

Using the .copy() method

original_list = ["apple", "banana", "cherry"]
copied_list = original_list.copy()
copied_list.append("date")
print(f"Original: {original_list}")
print(f"Modified copy: {copied_list}")
Original: ['apple', 'banana', 'cherry']
Modified copy: ['apple', 'banana', 'cherry', 'date']

The .copy() method creates a shallow copy of your list. This built-in approach offers a clean, readable syntax that clearly communicates your intent to duplicate data.

  • When you call original_list.copy(), Python creates a new list object with the same elements
  • Modifications to the copied list won't affect the original list structure
  • Like other shallow copy methods, it maintains references to nested objects

The example demonstrates this independence by appending "date" to the copied list. Notice how the original list remains unchanged while the copy includes the new element. This behavior makes .copy() ideal for scenarios where you need to experiment with list modifications without risking changes to your source data.

Using list comprehension

original_list = [10, 20, 30, 40]
copied_list = [item for item in original_list]
original_list[0] = 99
print(f"Original (modified): {original_list}")
print(f"Copy (unchanged): {copied_list}")
Original (modified): [99, 20, 30, 40]
Copy (unchanged): [10, 20, 30, 40]

List comprehension offers a concise, readable way to create list copies. The syntax [item for item in original_list] creates a new list by iterating through each element, performing a shallow copy similar to other methods.

  • The example demonstrates independence between lists. Modifying original_list[0] to 99 doesn't affect the copied version
  • List comprehension shines when you need to transform elements during copying. You can add operations to modify each item as it's copied
  • This method maintains excellent readability while offering the flexibility to filter or transform data in a single line

For simple copying tasks, list comprehension might seem verbose compared to .copy() or slice notation. However, its true value emerges when you need to combine copying with data transformation.

Advanced copying techniques

Beyond the basic copying methods we've explored, Python's copy module and map() function provide advanced capabilities for handling complex data structures and specialized copying scenarios.

Using copy module for shallow copies

import copy
nested_list = [1, [2, 3], 4]
shallow_copy = copy.copy(nested_list)
nested_list[1][0] = 'X'
print(f"Original: {nested_list}")
print(f"Shallow copy: {shallow_copy}")
Original: [1, ['X', 3], 4]
Shallow copy: [1, ['X', 3], 4]

The copy.copy() function creates a shallow copy of nested data structures. This means it duplicates the outer list structure while maintaining references to inner objects. When you modify nested elements like nested_list[1][0], both the original and copied lists reflect the change since they share references to the same nested objects.

  • The outer list gets a new memory location. You can verify this using Python's id() function
  • Inner lists remain linked. Changes to nested elements affect both lists
  • This behavior makes shallow copies memory efficient but requires careful handling of nested data

The example demonstrates this shared reference behavior. When we change the nested value to 'X', both lists show the modification because they point to the same inner list object.

Using copy module for deep copies

import copy
nested_list = [1, [2, 3], 4]
deep_copy = copy.deepcopy(nested_list)
nested_list[1][0] = 'X'
print(f"Original: {nested_list}")
print(f"Deep copy: {deep_copy}")
Original: [1, ['X', 3], 4]
Deep copy: [1, [2, 3], 4]

The copy.deepcopy() function creates a completely independent copy of your list, including all nested objects. Unlike shallow copying, this method recursively duplicates every object in the data structure, allocating new memory for each level.

  • When you modify the original list's nested element with nested_list[1][0] = 'X', the deep copy remains unchanged
  • Each nested object gets its own distinct memory location. This creates true independence between the original and copied data
  • Deep copying requires more memory and processing time. Use it when you need complete isolation between complex data structures

The output shows this independence in action. The original list displays the modified value 'X' while the deep copy preserves the initial value 2. This makes deep copying ideal for scenarios where you need to protect nested data from unintended modifications.

Using map() function to copy a list

original_list = ["hello", "world", "python"]
copied_list = list(map(lambda x: x, original_list))
print(copied_list)
print(f"Same list? {copied_list is original_list}")
['hello', 'world', 'python']
Same list? False

The map() function offers another approach to list copying by applying a simple lambda function to each element. This method creates a map object that we convert back to a list using the list() constructor.

  • The lambda function lambda x: x simply returns each element unchanged. It acts as an identity function that passes values through directly
  • This technique performs a shallow copy. The is operator returns False because we've created an entirely new list object
  • While functional and valid, this approach requires more keystrokes than alternatives like .copy() or slice notation

The map() method shines when you need to transform elements during the copying process. You can modify the lambda function to apply operations to each item as it's copied.

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When you encounter tricky Python scenarios like nested list copying or memory management issues, Claude acts as your personal code mentor. It can explain complex concepts, suggest optimal solutions, and help you understand the underlying principles of your code.

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Some real-world applications

Building on our exploration of Python's list copying methods, let's examine two practical scenarios where these techniques solve real business challenges.

Creating a filtered product list with [:] slice operator

The slice operator creates an independent copy of a product inventory list—enabling safe modifications without affecting the original data structure while maintaining efficient memory usage for simple data types.

products = ["Laptop", "Phone", "Tablet", "Headphones", "Monitor"]
electronics_copy = products[:]  # Create a copy using slice operator

# Filter out certain products from the copy
electronics_copy.remove("Headphones")
electronics_copy.append("Keyboard")

print(f"All products: {products}")
print(f"Electronics selection: {electronics_copy}")

This code demonstrates how to safely modify a copied list while preserving the original data. The slice operator [:] creates a new list electronics_copy with the same elements as products. Since we have an independent copy, we can freely modify it using remove() and append() methods without affecting the source list.

  • The remove() method eliminates "Headphones" from the copied list
  • The append() method adds "Keyboard" to the end
  • The original products list remains unchanged throughout these operations

This pattern proves especially useful when you need to create variations of your data while maintaining a pristine original version.

Managing server configurations with copy.deepcopy()

Deep copying with Python's copy.deepcopy() function enables developers to create completely independent copies of nested server configurations—a critical requirement when managing multiple deployment environments with different settings and credentials.

import copy

# Base configuration as a nested list [name, [settings]]
base_config = ["AppServer", ["localhost", 8080, ["admin", "password"]]]

# Create configurations for different environments
dev_config = copy.deepcopy(base_config)
prod_config = copy.deepcopy(base_config)

# Modify configurations for different environments
dev_config[1][0] = "dev-server"
prod_config[1][0] = "prod-server"
prod_config[1][2][0] = "prod-admin"

print(f"Base server: {base_config[1][0]}")
print(f"Dev server: {dev_config[1][0]}")
print(f"Prod server: {prod_config[1][0]}")
print(f"Prod username: {prod_config[1][2][0]}")

This code demonstrates how to manage multiple server configurations using Python's deepcopy() function. The base configuration stores server details in a nested list structure, including the server name, host, port, and credentials. Using deepcopy(), the code creates completely independent copies for development and production environments.

  • The base configuration uses "localhost" with port 8080 and default admin credentials
  • Development and production copies can be modified independently without affecting other environments
  • Each environment gets customized settings like different server names and admin usernames

The final print statements verify that each configuration maintains its unique values while the base configuration remains unchanged. This approach ensures clean separation between different deployment environments.

Common errors and challenges

Python developers frequently encounter three critical pitfalls when copying lists: assignment operators, loop modifications, and nested data structures require special attention to avoid unexpected behavior.

Mistaking = assignment for copying

The most common list copying mistake occurs when developers use the assignment operator = to duplicate a list. This creates a new reference to the same list object instead of creating an independent copy. The code below demonstrates how modifying the "copy" affects both variables unexpectedly.

original_list = [1, 2, 3, 4, 5]
copied_list = original_list
copied_list.append(6)
print(f"Original: {original_list}")
print(f"Copy: {copied_list}")

When you modify copied_list, the changes appear in original_list because both variables point to the same list in memory. The assignment operator creates a new reference instead of duplicating data. Let's examine the correct approach in the code below.

original_list = [1, 2, 3, 4, 5]
copied_list = original_list[:]
copied_list.append(6)
print(f"Original: {original_list}")
print(f"Copy: {copied_list}")

Using the slice operator [:] creates a true copy of the list in memory. This allows copied_list to be modified independently without affecting original_list. The slice operator duplicates the list structure and creates new references to each element.

  • Watch for this issue when passing lists as function parameters
  • Be especially careful with loops that modify list contents
  • Remember that simple assignment = only creates a new reference to the same data

This pattern appears frequently in data processing and manipulation tasks. Always use proper copying methods when you need independent list objects.

Problems when removing items during for loop iteration

Modifying lists while iterating through them with a for loop can lead to skipped elements and unexpected results. Python's iterator maintains internal counters that become misaligned when you remove items during iteration. The code below demonstrates this common pitfall.

numbers = [1, 2, 3, 4, 5]
for num in numbers:
    if num % 2 == 0:
        numbers.remove(num)
print(numbers)

When the loop removes an even number, it shifts the list indices. This causes Python to skip checking the next element entirely. The code below demonstrates a safer approach using list comprehension to filter elements.

numbers = [1, 2, 3, 4, 5]
numbers = [num for num in numbers if num % 2 != 0]
print(numbers)

List comprehension offers a cleaner solution by creating a new filtered list in a single step. The expression [num for num in numbers if num % 2 != 0] evaluates each element against the condition and builds a fresh list containing only odd numbers. This approach avoids the index shifting problems that occur when removing items during iteration.

  • Watch for this issue when filtering or removing elements based on conditions
  • Consider using list comprehension or creating a separate output list instead of modifying the original during iteration
  • Remember that removing elements changes list indices which can cause loop iteration to skip elements

Shallow copy limitations with nested dictionaries

Shallow copying nested dictionaries within lists can lead to unexpected behavior. When you use methods like [:] or .copy(), Python only creates independent copies of the outer list structure while maintaining references to the inner dictionaries. The code below demonstrates how modifying nested data affects both the original and copied lists.

users = [{"name": "Alice", "role": "admin"}, {"name": "Bob", "role": "user"}]
users_copy = users[:]
users_copy[0]["role"] = "guest"
print(f"Original: {users}")
print(f"Copy: {users_copy}")

Modifying the nested dictionary "role" in users_copy changes both lists because they share references to the same inner dictionaries. The shallow copy only duplicates the outer list structure. Let's examine the proper solution using deepcopy() in the code below.

import copy
users = [{"name": "Alice", "role": "admin"}, {"name": "Bob", "role": "user"}]
users_copy = copy.deepcopy(users)
users_copy[0]["role"] = "guest"
print(f"Original: {users}")
print(f"Copy: {users_copy}")

Using copy.deepcopy() creates completely independent copies of nested data structures. Each dictionary within the list gets its own memory space, allowing you to modify nested values without affecting the original data. The output shows Alice retaining her admin role in the original list while becoming a guest in the copy.

  • Watch for this issue when working with lists containing dictionaries, objects, or other mutable types
  • Remember that shallow copying methods like [:] or .copy() only duplicate the outer list structure
  • Consider using deepcopy() whenever you need true independence between complex nested data structures

Learning or leveling up? Use Claude

Claude combines advanced programming expertise with intuitive communication to help you tackle Python challenges more effectively. Whether you're debugging complex list operations or exploring memory management concepts, Claude provides targeted guidance that helps you grasp both theory and practical implementation.

  • List Copy Debugging: Ask "Why does my list copy still change the original?" and Claude will explain reference behavior and suggest the appropriate copying method.
  • Memory Management: Ask "When should I use shallow vs deep copy?" and Claude will break down the key differences with practical examples.
  • Performance Tips: Ask "Which list copying method is fastest?" and Claude will analyze performance implications of different approaches.
  • Code Review: Ask "Can you review my list copying implementation?" and Claude will identify potential issues and suggest improvements.
  • Best Practices: Ask "What are common mistakes when copying nested lists?" and Claude will outline pitfalls and their solutions.

Experience smarter Python development by signing up for free at Claude.ai.

For seamless integration into your development workflow, Claude Code brings AI assistance directly to your terminal, enabling rapid prototyping and efficient debugging without leaving your coding environment.

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